Then, the bug ran from −100 to 100. What distance did it cover? If the average speed of the bug during this run was 20 units per minute, how long did this run take?

200 units.

10 minutes.

Step-by-step explanation:

Distance = 100 - (-100)

= 100 + 100

= 200 units.

Speed = distance / time

20 = 200/ t

t =  200/20

= 10 minutes.

can someone me: the midsegment through the legs of an isosceles triangle is 4 in. find the sides of the triangle if its perimeter is 20 in. ,   and point g is the centroid of the right △abc with hypotenuse ab=18 in. find cg.

answer: the correct option is d.

explanation:

it is given that the triangle j'k'l' shown on the grid below is a dilation of triangle jkl using the origin as the center of dilation.

from the given graph it is noticed that k(4,8) and k'(2,4). let origin is defined by o and scale factor is defined by k, then

    (1)

distance formula,

put these values in equation (1).

therefore scale factor is     and option d is correct.