Please help me , btw it’s study island .

a. The water in the second tank decreases at a faster rate than the water in the first tank. The initial water level in the first tank is greater than the initial water level in the second tank.

Step-by-step explanation:

Step 1:

It is given that the time remaining in first tank is given by the equation y = -10x + 80. We can get the total water in the tank by substituting x = 0 in the equation. The total volume of water in first tank is 80 litres.

Step 2:

The value of y in the equation y = -10x + 80 will be 0 when the tank is fully empty. When y = 0 , 10x = 80, so x = 8. We can conclude that the first tank empties fully in 8 minutes.

In 8 minutes 80 litres of water is emptied from first tank. So the water in the first tank decreases at  rate of 80 / 8 = 10 litres per minute

Step 3:

As per the given table for the second tank, 60 litres of water remains when x =0. So the total volume of water in the second tank = 60 litres.

Step 4:

As per the given table for the second tank, the volume becomes 0 in 5 minutes. In 5 minutes 60 litres of water is emptied from second tank. So the water in  second tank decreases at rate of 60 / 5 = 12 litres per minute.

Step 5:

The initial volume of water in first tank is higher. The water in  second tank decreases at a faster rate than the first tank.

Step 6:

The only correct option is:

a. The water in  second tank decreases at a faster rate than the water in the first tank. The initial water level in  first tank is greater than the initial water level in the second tank.

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