What non-zero rational number must be placed in the square so that the simplified product of these two binomials is a binomial: (7t-10)(5t+Box )? Express your answer as a mixed number.

7 1/7.

Step-by-step explanation:

The middle 2 numbers in the expansion will be cancelled out  if one of them is + 50 t so the required  rational number is  50/7:

(7t - 10)(5t + 50/7) = 35t^2 - 50t + 350/7 t - 500/7)

=  35t^2 - 50t + 50t - 500/7)

= 35t^2 - 500/7)

So  50 / 7 = 7 1/7 (answer).

abde or 1,2,4, 5 is the answer

step-by-step explanation: