Apyramid has a regular hexagonal base with the side lengths of 4 and a slant height of 6. find the total area of the pyramid..

113.57 unit²

Step-by-step explanation:

Surface area of a pyramid with regular hexagonal base

= Area of slant sides + area of Hexagonal base

Area of one slant side = (side of base) × slant height

                                    = × 6 × 4

                                    = 3 × 4

                                    = 12 unit²

Since hexagonal pyramid has 6 slant sides.

So area of sic slant sides = 6 × 12 = 72 unit²

Now for the area of hexagonal base we will take triangle ABC.

∠BAC = 60°    [angle formed at center = ]

and ∠CAD = 30°

Now tan 30° = =

AD =

Now hexagonal base area = 6 × [ (BC)(AD)]

6 × [ × ] =  

Therefore area of the pyramid = 72 + 41.57 = 113.57 unit²

10/60

step-by-step explanation:

if you divide 10 by 60 the answer is 0.166666 while if you divide or solve the other problems it equals 0.6

the 3rd on is correct

step-by-step explanation: