The probability that a randomly-selected U. S. household owns a pet is 0.39. Given that a household owns a pet, the probability that it owns a dog is 0.67 and the probability that it owns a cat is 0.24. a) Given that a household owns a pet, what is the probability that the pet is not a cat or dog?

0.2508

Step-by-step explanation:

The question asks for a conditional probability.

P(a household owns a dog if it owns a pet) = 0.67

Then P(a household does not own a dog if it owns a pet) = 1 - 0.67 = 0.33

P(a household owns a cat if it owns a pet) = 0.24

Then P(a household does not own a cat if it owns a pet) = 1 - 0.24 = 0.76

P(if a household owns a pet but the pet is not a cat or dog) = P(if a household owns a pet, it does not own a cat) × P(if a household owns a pet, it does not own a dog) = 0.33 × 0.76 = 0.2508

answer: yes i agree that you should not put it on/p>

step-by-step explanation: the reason for this is that it wastes other peoples time and also make them fail as well and that is never good.