To find the probability that the car selected randomly does not have a GPS navigation system, answer the following questions. (a) Identify the event whose probability we are required to find. Event: What is the given requirement for the randomly selected car? (b) How many ways could the above event occur? From the total list of cars, how many of them meet the new requirement? (c) What is the total number of possible outcomes? How many cars did the rental car agency have available? (d) Compute the probability for this event. Give the exact answer in the form of fraction. The probability = To get the probability, divide the number of outcomes A is comprised of by the total number of outcomes for the experiment.

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.

the diameter is 16 cm. are you a teacher?

step-by-step explanation:

answer: options

step-by-step explanation: