City park is a right triangle with a base of 40yd and a height of 25yd. On a map, the park has a base of 40in and a height of 25in. How do the areas of the park and the map of the park compare

every square yard of the park there is one square inch on the map

Step-by-step explanation:

First we will calculate the real area and the map area

p = city park area

p = ( 40yd * 25yd ) / 2

p = 1000yd² / 2

p = 500yd²

m = map area

m = ( 40th * 25th ) / 2

m = 1000th² / 2

m = 500th²

if we compare the 500yd² of the park with the 500th² we realize that there is a relationship that for every square yard of the park there is one square inch on the map

show us the graphs dude

step-by-step explanation:

answer:   35 % is the probability of a late departure or an early arrival.

step-by-step explanation:

let l represents the late departure and e represents the early departure.

then, according to the question,

p(l) = 12 %,   p(e) = 27 % and = 4 %

and, we have to find out,

but, we know that,

which is the required equation that will use to find the probability of a late departure or an early departure.

therefore,   the probability of a late departure or an early arrival =   35 %