Last year at Townsburg High School, 30% of the graduating seniors took the ACT exam, 37% of the graduating seniors took the SAT exam, and 22% of graduating seniors too both exams. A student is selected at random. If the student took the ACT, what is the probability that they also took the SAT?

73.33% probability that they also took the SAT

Step-by-step explanation:

We have these following two events.

Event A: Taking the ACT exam. So P(A) = 0.3.

Event B: Taking the SAT exam. So P(B) = 0.37.

The conditional probability formula is:

In which P(B|A) is the probability of event B happening given that A has happened, is the probability of both events hapenning.

22% of graduating seniors too both exams.

This means that

If the student took the ACT, what is the probability that they also took the SAT?

73.33% probability that they also took the SAT

10 * 563.67 = 5636.7

number one is the correct answer

step-by-step explanation: dogs and cats are mentioned, no other animals