What’s the solution to 3y=x - 4 and 6x - 6y = 8

(0, - )

Step-by-step explanation:

Given the 2 equations

3y = x - 4 → (1)

6x - 6y = 8 → (2)

Rearrange (1) expressing x in terms of y by adding 4 to both sides

x = 3y + 4 → (3)

Substitute x = 3y + 4 into (2)

6(3y + 4) - 6y = 8 ← distribute and simplify left side

18y + 24 - 6y = 8

12y + 24 = 8 ( subtract 24 from both sides )

12y = - 16 ( divide both sides by 12 )

y = = -

Substitute y = - into (3) and solve for x

x = 3(- ) + 4 = - 4 + 4 = 0

Solution is (0, - )

the image of (6, 9) under a dilation is (4, 6). the scale factor is

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i