A test preparation claims that more than 50% of the students who take their test prep course improve their scores by at least 10 points. Instead of advertising the percentage of customers who improve by at least 10 points, a manager suggests testing whether the mean score improves at all. For each customer they record the difference in score before and after taking the course (AfterminusBefore). a) State the null and alternative hypotheses. b) The P-value from the test is 0.65. Does this provide any evidence that their course works? c) From part b, what can you tell, if anything, about the mean difference in the sample scores? a) State the hypotheses.

If the mean score on a creativity test is 20, the standard deviation is 5, and the distribution is normal, the percentage of people who would obtain scores between 15 and 25 is a) 34% b) 14% + 34%= 48% c) 50% d) 34% + 34%= 68%

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hears my work

students in a class take a test and the mean score is 95 and the standard deviation is 8. If the lowest possible score to pass the test is 72, what percentage of students did not p Algebra -> Average -> SOLUTION: Students in a class take a test and the mean score is 95 and the standard deviation is 8.

idk the answer but just put a

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i you goofed up when writing this, because hnot is not a word minusf is not either. i cannot answer   because of that.

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