According to government data, the probability that an adult was never in a museum is 15%. In a random survey of 10 adults, what is the probability that two or fewer were never in a museum

0.8202

Step-by-step explanation:

Probability an adult was never in a museum = probability of success = p = 15% = 0.15

To find probability that 2 or fewer of the 10 samples selected were never in a museum is given by:

P(X=2) or P(X=1) or P(X=0).

Where

P(X=r) = nCr * p^r * q^n-r

and n=10, p =0.15, q=0.85

When r = 2

P(X=2) = 10C2 * 0.15² * 0.85^8 = 0.2759

When r = 1

P(X=1) = 10C1 * 0.15 * 0.85^9 = 0.3474

When r = 0

P(X=0)= 10C0 * 0.15^0 * 0.85^10 = 0.1969

Hence probability of having 2 or fewer adults who never visited the museum = 0.1969 + 0.3474+ 0.2759 = 0.8202

option: d is the correct answer.

d) none of the above.

step-by-step explanation:

clearly from the figure attached to the question we could see that there is no shape given. hence without any shape given in the figure and after rotation we can't obtained a square pyramid.

since, to obtain a image we need a proper figure of the pre-image so that it can be transformed.

hence, the correct answer is:

d) none of the above.

step-by-step explanation:

there are 70 more legs than eyes at the dog show (196 – 126 = 70). dogs have two more legs than eyes, and humans have the same number of legs as eyes. thus 70 is twice the number of dogs at the show, so the number of dogs is half of 70, which is 35. to get the number of humans, subtract 35 from 63: 63 – 35 = 28.

step-by-step explanation: