A local train has departed from the station A at ten o'clock with the speed of 55 km/h. One and a half of an hour later an express has departed from the station B, which is 360 km far from the station A, and it went toward the local train with the speed of 130 km/h. At what time and how far from the station A will the two trains meet ?

!0.00360 km

><11.30

55km/h                               130 km/h

Step-by-step explanation:

in a one and a half hour the distance between the train will be

360- 55*1,5=277.5 km

in an hour the distance between the trains is less with 55+130=185 km

to meet the trains , the distance between them should be zero

277.5 - 185*x=0

+185 x             +185 x

277.5=185x

x=277.5/185 hours

x= 1.5 hours  after 11.30

They meet at 13.00

the distance will be   55*3 =165 km from the station A

the size of the resulting matrix is 1-by-3.

step-by-step explanation:

the size of the two matrices given are as follows:

no .of rows of matrix 1 = 1

no .of columns of matrix 1 = 3

no .of rows of matrix 1 = 3

no .of columns of matrix 1 = 3

to find the size of the resulting matrix without actually solving the multiplication of the matrix, this is what you do:

if resulting matrix = matrix 1 * matrix 2

no. of rows of the resulting matrix = number of rows of matrix 1

no. of columns of resulting matrix = number of columns of matrix 2

note: the order of the matrices matter!

it is true

step-by-step explanation:

all the combinations add up i used   calculator