If there is 4 green marbles and 7 orange marbles in box 1 and 4 green marbles and 5 orange marbles in box 2 what is the probability of picking 2 green marbles?

Out of which box?

I'll answer for Box 1 and Box 2.

So in Box 1, you have 4 + 7 = 11 marbles in total.

Probability of drawing first marble green.

4 (green marbles) / 11 (marbles in total.

Probability of drawing second marble green:

Assuming you already drew a green marble, there's one less green marble, and one less marble in total:

3 / 10.

So the probability of drawing 2 green marbles in Box 1 is:

4 / 11 * 3/10 (since they're independent events) = 12/110 = 6/55

Probability of drawing 2 green marbles in Box 1 is: 6/55.

Now let's move on to Box 2:

You have 4 + 5 = 9 marbles in total.

Probability of drawing first marble green:

4 / 9.

Probability of drawing second marble green:

3/8

Multiply them since they're independent events:

4/9 * 3/8 = 12/72 = 6/36 = 1/6.

Probability of drawing 2 green marbles in Box 2 is 1/6.

5050 i think

step-by-step explanation: