An after-shave lotion contains 45% ethyl alcohol. How much water must be added to 8 fluid ounces of this lotion to reduce it to one which is 70% nonalcoholic?

\boldsymbol{\mathbf{4 ounces water we need to add.}}

An after shave lotion contains 45% of ethyl alcohol

i.e 100% - 45% = 65% nonalcoholic

As mentioned, we have 8 ounces of fluid and that contains 45% of ethyl alcohol.

i.e

We need fluid which 70% nonalcoholic.

i.e 100 - 70 = 30% of alcohol.

Then there is already 3.6 ounces of alcohol in fluid.

As required, Let consider 3.6 ounce is 30% of alcohol.

70% must be other liquid.

That is equal to =

=

= 8.4 Ounces Of other liquid.

Then total ounces of the lotion is

= 3.6 + 8.4

= 12 ounces.

Water required to add is,

= 12 - 8

=

1,8,15,22,29,36,43,50

step-by-step explanation:

answer: 5 17/33 % (to the tenth)

step-by-step explanation:

he guessed: 34.5 pounds

actual weight is 32.7

there for he is off:

34.5 -32.7 = 1.8

32.7 is the 100%

1.8 represents %? of 32.7

therefore:

32.7   - 100%

1.8     -     x%

x= 1.8*100%/32.7% = 18*100%/327%

x=1800%/327%   = (5 165/327)%

to the tenth:

5 17/33 %