You are planning to make an open rectangular box from a 33-in.-by-65-in. piece of cardboard by cutting congruent squares from the corners and folding up the sides. What are the dimensions of the box of largest volume you can make this way, and what is its volume?

Volume = 6783.27inch³

H = 6.951inch

L = 51.098inch

W = 19.098inch

Step-by-step explanation:

From the given information:

Let h = side length and height of the box

L = length of the box

W = width of the box

V = volume of the box

We have that:

L = 65-2h

W = 33-2h

V = L×W×h

Therefore we have

V = (65-2h)(33-2h)×h

V = (2145-130h-66h+4h²)×h

V = 2145h-196h²+4h³

By differentiating V w.r.t h, we have

V' = 2145-392h+12h²

V = 12h²-392h+2145

Using Almighty formula we have

h = 392+/-√392²-4(12)(2145)/2(12)

h = 6.951 or 25.716

Thus, we find L,W and V.

We use the least value of h in order not to get a negative value of volume, length and width

L = 65-2h = 65-2(6.951) = 51.098

W = 33-2h = 33-2(6.951) = 19.098

V = LWH = 51.098×19.098×6.951 = 6783.2696inches

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form