For what value of x is the double product of the binomials x+2 and x–2 is 16 less than the sum of their squares?

pls help I’m confused

for all values of x = 2 is the double product of the  binomials x+2 and x–2 is 16 less than the sum of their squares

Step-by-step explanation:

By Using the difference of two square:

The product of the binomials:

Double the product yields =    ----- equation (1)

However, the sum of their squares can be expressed as follows:

16 less than that will be:

            ----------- equation (2)

NOW; the question says for what value of the "x" are those two equation equal to each other;

To tackle the problem; we equate equation (1) and equation (2) together.

So; now we can have:

  =

In this scenario; we found out that the left-hand side is equal to the right-hand side.

So;

We therefore conclude that for all values of x = 2 is the double product of the  binomials x+2 and x–2 is 16 less than the sum of their squares

Also, we can say that for all values of "x" = for all intervals or for set notations.

the answer is c.

for continuous functions, they continue in the same pattern and you have to find that pattern kinda like slope

answer: options?

step-by-step explanation: