Boyle's Law states that when a sample of gas is compressed at a constant temperature, the pressure P and volume V satisfy the equation PV = C, where C is a constant. Suppose that at a certain instant the volume is 1000 cm3, the pressure is 80 kPa, and the pressure is increasing at a rate of 20 kPa/min. At what rate is the volume decreasing at this instant?

The volume is decreasing at a rate of 250 cm^3/min

Step-by-step explanation:

From Boyle's law, the relationship between pressure (P) and volume (V) is inverse in which increase in one quantity (P) leads to a corresponding decrease in the other quantity (V).

Pressure at a certain instant (time) = 80 kPa

Rate at which pressure is increasing = 20 kPa/min

Time required for this increase = pressure ÷ rate = 80 ÷ 20 = 4 min

Volume = 1000 cm^3

Rate at which volume is decreasing at the same time pressure is increasing = 1000 ÷ 4 = 250 cm^3/min

x=-2

infinite number of lines, so there is an infinite number of equations.

step-by-step explanation:

there are an infinite number of line that passes through the point (-2,5)

x=-2   is one line that passes through the point

y = 5 is another line that passes through the point

(these two lines are perpendicular to each other).

since the number of   numbers are infinite and the slope is the ratio of two numbers,(change in y over change in x) we can have an infinite number of slopes.     our only condition is that it passes through the point (-2,5)

example 2 – simplify: step 1: completely factor both the numerators and denominators of all fractions. step 2: change the division sign to a multiplication sign and flip (or reciprocate) the fraction after the division sign; essential you need to multiply by the reciprocal. step 3 : cancel or reduce the fractions.