Please help me!! Will give brainliest! The equation of function h is h(x) = 1/2(x - 2)^2. The table shows some of the values of function m.
Part A: What is the value of h(4) - m(16)?
Part B: If both of these fonctions are graphes on the same coordinate plane, how far apart are the y-intercepts?
Part C: What values of x does m(x) excess h(x)?

Part A)

Part B) The Y- intercepts are four units apart.

Part C) m(x) never exceeds h(x)

Step-by-step explanation:

Part A) What is the value of h(4)-m(16)

step 1

Find the value of h(4)

we have

For x=4

substitute in the quadratic equation

step 2

Find the equation of m(x)

Find the slope m

The formula to calculate the slope between two points is equal to

take two points from the data

(8,2) and (10,3)

substitute in the formula

Find the equation in point slope form

we have

substitute

Convert to slope intercept form

Isolate the variable y

Convert to function notation

Find the value of m(16)

For x=16

substitute the value of x in the function m(x)

Find  h(4)-m(16)

substitute the values

therefore

Part B) If both of these functions are graphed on the same coordinate plane, how far apart are the y-intercepts?

we know that

The y-intercept is the value of y when the value of x is equal to zero

Find the y-intercept of h(x)

For x=0

The y-intercept of h(x) is the point (0,2)

Find the y-intercept of m(x)

For x=0

m(x)=\frac{1}{2}(0)-2=-2

The y-intercept of m(x) is the point (0,-2)

To find out how far apart are the y-intercepts, determine the difference between the y-intercepts

see the attached figure to better understand the problem

Part C) What values of x does m(x) excess h(x)?

we know that

Looking at the attached figure

The graphs of f(x) and m(x) not intersect

The graph of f(x) is above the graph of m(x)

The value of f(x) will always be greater than the value of m(x)

therefore

m(x) never exceeds h(x)