A particle travels along the xx-axis such that its velocity is given by v(t)=t^{0.3}\cos\left(2t+3\right).v (t)=t 0.3 cos(2t+3). If the position of the particle is x=3x=3 when t=0,t=0, what is the position of the particle when t=3?t=3? You may use a calculator and round your answer to the nearest thousandth.

f(2x−x2)=−3x2+6x−1

step-by-step explanation:

set up the composite function and evaluate.

f(2x−x2)=−3x2+6x−1

because they could drop even lower..

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

do have an equation or graph or

step-by-step explanation: