In a certain country, the true probability of a baby being a boy is 0.511. Among the next eight randomly selected births in the country, what is the probability that at least one of them is a girl?

The probability that at least one of 8 babies born is a girl  is 0.9954.

Step-by-step explanation:

Let X = a baby born is a girl.

The probability of a baby born being a girl is,

P (G) = 1 - P (B)

        = 1 - 0.511

     p  = 0.489

The number of births is, n = 8.

The random variable X follows a Binomial distribution with parameters n and p.

The probability mass function of the Binomial distribution is:

Compute the probability that out of 8 births at least one is a girl as follows:

P (X ≥ 1) = 1 - P (X < 1)

             = 1 - P (X = 0)

Thus, the probability that at least one of 8 babies born is a girl  is 0.9954.

36 is the final answer! : )

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