An 80-foot rope is attached to a boat 7 feet above the water level and a boy jumps over the wake while wakeboarding. What is the distance between his hands and the water level ?

2.81 feet.

Step-by-step explanation:

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We have been given that an 80-foot rope is attached to a boat 7 feet above the water level and a boy jumps over the wake while wake-boarding. We are asked to find the distance between boy's hands and the water level.

Let h represent opposite side of right triangle.

We can see that rope forms a right triangle with boat and water level, where 80 feet is hypotenuse of triangle to 87 degree angle.

The distance between boy's hands and the water level would be 7 feet minus the opposite side of right triangle.

We know that cosine relates the adjacent side of right triangle with hypotenuse.

Therefore, the distance between boy's hands and the water level is approximately 2.81 feet.

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step-by-step explanation:

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