Find the area of the shaded region.
60
5 cm
A ~ [?] cm2
iter a decimal rounded to the nearest tenth

76.3 cm^2 to the nearest tenth.

Step-by-step explanation:

The area of the clear segment

= area of the sector - area of the triangle

=  1/6π r^2 - area of the triangle.

If we halve the equilateral triangle we have a 30-6-90 triangle whose height  is 5 *  5*√3/2.

Area of the triangle = 1/2 base * height

= 1/2 * 5 * 5*√3/2

Area of the segment

= 1/6 * π 5^2 -  12.5 * √3/2

= 2.265 cm^2.

So the area of the shaded part

=   π 5^2 - 2.265

= 76.27 cm^2.

1. 3.4/4

2. 0.8/7

3. 0.5 x 3

4. 0.9 x 6

5. 10.8

6. 2.35

7. 0.567

8. 9.35

9. 0.02

10. 0.06

11. 0.16

12. 0.42

13. 0.63

14. 5.6

15. 8.1

16. 9.9

17. 0.28

18. 0.48

19. 0.27

20. 0.49

21. 0.45

22. 0.72

23. 0.9

24. 0.88

25. 0.75

26. 0.16

27. 0.328

28. 0.495

29. 0.72

30. 1.068