Part A: Identify the minimum value, lower quartile (Q1), median, upper quartile (Q3), and maximum value from the box and whisker plot.

Part B: Calculate the interquartile range (IQR). What does this tell you about the problem situation?

Part C: In a short paragraph, explain in your own words your work in steps A and B.

See explanation

Step-by-step explanation:

Part A: The box and whisker plot shows

Min = 15

Q1 = 23

Q2 = Median = 36

Q3 = 38

Max = 50

Part B: The interquartile range is

The interquartile range, which tells us how far apart the first and third quartile are, indicates how spread out the middle 50% of our set of data is. The interquartile range is not sensitive to outliers. The interquartile range rule is what informs us whether we have a mild or strong outlier. To look for an outlier, we must look below the first quartile or above the third quartile. How far we should go depends upon the value of the interquartile range.

Part C: To find the Min value, look at the left endpoint of the box and whisker plot and to find the Max value, look at the right endpoint of the box and whisker plot. The box (rectangle) has left endpoint at Q1 and right endpoint at Q3. The median is the value marked with vertical line in the middle of box (rectangle).

By the definition, the interquartile range is the difference betweeen Q3 and Q1.

answer: ratio of volume of cone (with 3 times the height and equal diameter) to volume of cylinder is 2 to 1. the value of π is not used.

step-by-step explanation:

radius is diameter/2 = 4.

area of circle is π r^2.

volume of cylinder is height × area of base = hπr^2 = 3(4^2) π = 48π cubic inches.

not knowing the formula for volume of cone, i calculate it using calculus (which is for calculating things).

volume of cone is integral 0 to h area(y) dy. area(y) is π r(y)^2. r(y) runs r to zero as y runs zero to h, r(0) = r, r(h) = 0.

r(y) = r - r/h y

area(y) = π (r - r/h y)^2 = π (r^2 - 2r^2y/h + r^2y^2/h^2) = π r^2(1-2y/h+y^2/h^2)

antiderivative area(y) = π r^2 (y-y^2/h+y^3/(3h^2))

integral 0 to h = π r^2(h-h^2/h+h^3/(3h^2) - (0)) = π r^2(h - h + h/3) = π r^2(h/3) = π/3 r^2 h

volume of this cone is π/3(4^2)18 cubic inches.

= 6 16 π = 96π cubic inches.

cone has twice the volume, 96/48.

cone height is 6 times the cylinder.

ratio of volume formula: π r^2 cancels.

cone over cylinder ratio is 6h/3 to h, 2 to 1.