What is the amplitude, period, and phase shift of f(x) = −4 sin(2x + π) − 3? Amplitude = 4; period = π; phase shift: x equals pi over two Amplitude = −4; period = 2π; phase shift: x equals pi over two Amplitude = 4; period = π; phase shift: x equals negative pi over two Amplitude = −4; period = 2π; phase shift: x equals negative pi over two

The correct option is option (c)

Therefore amplitude = 4, period= π and

Step-by-step explanation:

Amplitude: The amplitude of a wave is a maximum displacement of a particle from its rest position

Period: The ratio of wavelength to the velocity.

Phase shift: The phase shift represents the amount a wave has shifted horizontally from the the usual position.

The equation of a wave is

f(x) = a sin(bx - c)+d

Where

amplitude = |a|

Given equation of wave is

f(x) = -4sin (2x + π) -3

Here a=-4, b=2, c = -π, d = -3

Amplitude = |-4| = 4

Therefore amplitude = 4, period= π and

step-by-step explanation:

one of the most important purposes of surface treatment is to alter surface properties according to the requirement of specific applications. for example, hydrophobic coating has been utilized on windshield and eyeglasses. gold atom monolayer on substrate has become a popular surface bioconjugation strategy.