A bag contains 43 U. S. quarters and seven Canadian quarters. (The coins are identical in size.) If six quarters are randomly picked from the bag, what is the probability of getting at least one Canadian quarter

0.616

Step-by-step explanation:

The number of Us quarters is 43 while the number of Canadian quarters is 7.

The number of quarters we are to pick is 6

Mathematically, the probability of getting at least one Canadian quarter = 1 - probability of getting no Canadian quarter

This means we have to calculate the probability of getting no Canadian quarter first.

The total number of possible outcomes is 50C6 = 15,890,700

If we are to get all to be US quarters, that means we are getting exactly 6 out of 43 = 43C6 = 6,096,454

Hence, probability of no Canadian quarters is 6,096,454/15,890,700 = 0.384

The probability of at least 1 Canadian quarters is thus 1-0.384 = 0.616

i can't see the picture : /

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.