What is the y-value of the vertex of the function f(x)=-(x-3)(x+11)?

y = - 49

Step-by-step explanation:

The vertex lies on the axis of symmetry which is at the midpoint of the zeros.

To find the zeros, let f(x) = 0, that is

(x - 3)(x + 11) = 0

Equate each factor to zero and solve for x

x - 3 = 0 ⇒ x = 3

x + 11 = 0 ⇒ x = - 11

= = = - 4

To find the y- coordinate of the vertex evaluate f(- 4)

f(- 4) = (- 4 - 3)(- 4+ 11) = (- 7)(7) = - 49

Step-by-step explanation:

hello :

f(x)=-(x-3)(x+11) = -(x²+11x-3x-33)

f(x) = -x²-8x+33 = -(x²+8x-33)

f(x) = - (x²+8x+16-16-33)=-(x²+8x+16) + 49

f(x) = - (x+4)²+49    vertex form

the y-value of the vertex of the function is 49  when x= - 4

$450

step-by-step explanation:

first, you have to multiply 150x2=300

next, you have to add 150+300= 450

walter needs to make at least 5 more cookies but no more than 40. 5 ≤ x ≤ 40

step-by-step explanation:

20 ≤ x + 15 ≤ 55

subtract 15 from all parts

20-15 ≤ x + 15-15 ≤ 55-15

5 ≤ x ≤ 40

this means how many more cookies he has to make

walter needs to make at least 5 more cookies, but no more than 40 cookies; 5 ≤ x ≤ 40