What is an equation of the line that passes
through the points (3, 3) and (6, -1)?

y=-4/3x+7

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(-1-3)/(6-3)

m=-4/3

y-y1=m(x-x1)

y-3=-4/3(x-3)

y=-4/3x+12/3+3

y=-4/3x+4+3

y=-4/3x+7

Step-by-step explanation:

ghanami

Step-by-step explanation:

Hello : let  A(3,3)    B(6,-1)

the slope is :   (YB - YA)/(XB -XA)

(-1-3)/(6-3)  = -4/3

an equation is the line is : y = ax+b        a is a slope

y = (-4/3)x+b

but this line passes by (6;-1)

so : -1 = (-4/3)(6)+b

b = 7

the equation is : y = (-4/3)x+7

i found two solutions,   n = 2 • ± √3 = ± 3.4641

step-by-step explanation: