At a school carnival, the diameter of the mat of a trampoline is 12 feet and the diameter of its metal frame is 14 feet. What is the length, in feet, of the metal frame that surrounds the trampoline? Use 3.14 for π and round your answer to the nearest tenth.

The length, of the metal frame that surrounds the trampoline is 44.0 feet.

Step-by-step explanation:

Given:

At a school carnival, the diameter of the mat of a trampoline is 12 feet and the diameter of its metal frame is 14 feet.

Use 3.14 for π.

Now, to find the length, in feet, of the metal frame that surrounds the trampoline.

As given, diameter is 14 feet.

So, radius (r) =

Now, to get the length of the metal frame we put formula of circumference:

So, rounding into nearest tenth = 44.0 feet.

Therefore, the length, of the metal frame that surrounds the trampoline is 44.0 feet.

44.0 feet

Step-by-step explanation:

1.4

2.3

step-by-step explanation:

the formula for the constant of variation is

y= kx

divide each side by x

y/x =kx/x

y/x =k

we know a and y

1.   y/x = k

4/1 =4

check the other values to make sure they are the same

8/2 = 4   12/3 =4   and 16/4 =4  

the constant of variation is 4

2.   y/x = k

3/1 =3

check the other values to make sure they are the same

6/2 = 3   9/3 =3   and 12/4 =3  

the constant of variation is 3

correct answer:

b.(19,-2)