You have a bag of 20 marbles. Twelve of the marbles are green and eight of the marbles are yellow. You draw three marbles out of the bag without replacement. What is the probability that all three marbles will be yellow? Is this an example of a binomial experiment?

The combined probability of picking three yellow marbles  

It is NOT a binomial experiment.

Step-by-step explanation:

Here, the total number of marbles in the bag = 20

The total number of green marbles =  12

The total number of yellow marbles = 8

Now, let E : Event of picking a picking a yellow marble

So, the probability of picking FIRST yellow marble =

Now,as the marbles is again picked WITHOUT REPLACEMENT:

So, total marbles in the bag now = 20 -1 = 19 and yellow marbles = 8 -1 = 7

P(Picking second yellow marble) =  

P(Picking Third yellow marble) =  

Now the combined probability of picking three yellow marbles

=  

Also, the binomial experiment =  

Solving for n = 20 and x  = 3 , p = 2/5 and q = 3/5 we get:

P =  ≠

Hence, it is NOT a binomial experiment.

use an equation of ratios to determine the amount of gas needed to fill the tank.

    0.2             0.8

  =    

288.75             x

                                                              231 gal

so, 0.2x = (0.8)(288.75 gal), and x = = 1155 gal.

                                                                0.2

it would take 1155 gal. to fill the tank.

the cost would be

1155 gal         $3

* = $3465   (answer)

      1           1 gal

hope this you

were is the equation