Find the slope-intercept form of the line whose slope is 66 and that passes through the point (negative 5 comma 10 )(−5,10).

y = 66x + 340

Step-by-step explanation:

The question asks to give the slope-intercept equation of a line with the slope given and it passes through a given line.

Generally, the equation of a line is given by:

y = mx + c, where m is the slope and c is the intercept. We have the slope given but we do not have the intercept. Hence, the first thing we do is to find the value of the intercept. We calculate that as follows:

since the line passes through a point, we substitute the values of the ordinate and the abscissa in the general equation of the line.

This means; 10 = 66(-5) + C

C = 10 + 330 = 340

Hence, the general equation of the line is;

y = 66x + 340

2 is the final ! : )

translate k to n and reflect across the line containing jk.