In the air, it had an average speed of 16m/s . In the water, it had an average speed of 3 m/s before hitting the seabed. The total distance from the top of the cliff to the seabed is 127 meters, and the stone's entire fall took 12 seconds. How long did the stone fall in air and how long did it fall in the water?

Time in the air  t₁  =  7 s

Time in the sea t₂ =  5 s

Step-by-step explanation:

We will use the equation:   v =  d/t , where:

v is the average speed,

d the distance traveled, and

t time doing the trip

From v = d/t    ⇒  d = v*t

Therefore, if we call t₁ time in the air, and t₂ time in the sea, according to problem statement, we have:

t₁  +  t₂  = 12        (1)

16*t₁  +  3*t₂  = 127    (2)

A two equation system, from equation (1) we get

t₂  = 12 - t₁

And by substitution in equaton (2)

16*t₁  + 3 * ( 12 - t₁ ) = 127

16*t₁  + 36 - 3*t₁  = 127

13*t₁   = 91

t₁  = 91 /13

t₁ = 7 s

And    t₂  = 12 - 7

t₂ = 5 s

question: how many people can she serve?

answer: she can serve 16.66666667 people. so she can only give 16 people a complete serving.

question: does she have enough ice cream for her guests?

answer: no. explanation: she only has enough for 16 people to have a full serving. however, she can give a 17th person a partial serving.

answer: sensy

step-by-step explanation: