Find the mass and center of mass of the lamina that occupies the region D and has the given density function rho. D is the triangular region enclosed by the lines y = 0, y = 2x, and x + 2y = 1; rho(x, y) = x

m=1/300 du

Step-by-step explanation:

we have that m=∫∫rho(x,y)dA for this we must find the limits of integration (according to the graph1)

On the x axis: if y=2x and x+2y=1 then y=2x and y=(1-x)/2 ⇒ 2x=(1-x)/2 ⇒ 4x=1-x ⇒ 5x=1 ⇒ x=1/5; on the y axis y=0 and y=1/2

m=∫∫rho(x,y)dA (view the graph 2)

rectangle that is ther answer you

step-by-step explanation:

4x and 6y

im not sure though