A researcher records the following response times to a visual stimulus: 23 ± 3.1 ( M ± SD) s. Assuming these data are normally distributed, what is the probability that participants responded in 20 s or less

0.1666

Step-by-step explanation:

A researcher records the following response times to a visual stimulus: 23 ± 3.1 ( M ± SD) s. Assuming these data are normally distributed, what is the probability that participants responded in 20 s or less

z=X-U/SD

z=(20-23)/3.1

z=-0.9677

checking the negative part of the z score table. we go to

-0.97

that is -0.9 under 0.07

the value we get is 0.1666

P(x<20) means that P(z<-0.97)

0.1666

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

mx+89b(-98)nb

step-by-step explanation: