Noise levels at 6 airports were measured in decibels yielding the following data: 148,155,177,141,173,141 Construct the 98% confidence interval for the mean noise level at such locations. Assume the population is approximately normal. Step 1 of 4 : Calculate the sample mean for the given sample data. Round your answer to one decimal place.

Complete question is:

Noise levels at 6 airports were measured in decibels yielding the following data: 148,155,177,141,173,141 Construct the 98% confidence interval for the mean noise level at such locations. Assume the population is approximately normal.

Step 1 of 4 : Calculate the sample mean for the given sample data. Round your answer to one decimal place.

step 2 : sample standard deviation two decimal places

step 3 find critical value of confidence level round three decimal places

step 4 construct the 98 percent confidence interval round two decimal places

Answer is (required in given question):

155.8

Step-by-step explanation:

answer: was that a question or answer?

step-by-step explanation:

a 4/6 = 9/12   not proportional

step-by-step explanation:

to find which are not proportional, we can use cross products

if it is true, they are proportional.   if it is not true, they are not proportional.

a 4/6 = 9/12

4* 12 = 6*9

48 = 54

not this is not proportional  

b 2/3 = 12/18  

2* 18 = 3 * 12

36 = 36

this is proportional

c 5/4 = 10/8  

5*8 = 4*10

40 = 40

this is proportional

d 7/5 = 35/25

7*25 = 5 * 35

175 = 175

is proportional