For what value of a does (one-ninth) Superscript a + 1 Baseline = 81 Superscript a + 1 Baseline times 27 Superscript 2 minus a? –4 –2 2 6

-4

Step-by-step explanation:

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The value of a is -4

Step-by-step explanation:

=    ×    ------------------------------------(1)

No solve this, we need to take note that 9 = 3² , 81 =     and 27 =

Now, we are going to replace 9 , 81 and 27 by  3²,    and respectively in equation(1)

 =    ×     ------------------------------(2)

also  =    

we are going to replace     by     in equation (2)

     =    ×  

We can now open the parenthesis

 =    ×  

At the right-hand side of the equation, we will apply the law of indices that state   ×  =    

This implies we will take just 3 and then add-up all the powers

 =

The 3 on the left-hand side will cancel-out the 3 on the right-hand side leaving us with just the powers

-2a - 2 = 4a + 4 + 6 - 3a

-2a - 2 = 4a + 10 - 3a

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Which means we will take all the digits with variable to the left-hand side and then take all the digits standing alone to the right-hand side of the equation

-2a - 4a + 3a = 10 + 2

-6a + 3a = 12

-3a = 12

Divide both-side of the equation by -3

=

a = -4

Therefore, the value of a is -4

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step-by-step explanation: