The graph of y ≤ 3x + 1 and y ≥ –x + 2? Check all that apply. 1.The slope of one boundary line is 2.
2.Both boundary lines are solid.
3.A solution to the system is (1, 3).
4.Both inequalities are shaded below the boundary lines.
5.The boundary lines intersect.

2.Both boundary lines are solid.

3.A solution to the system is (1, 3).

5.The boundary lines intersect.

Step-by-step explanation:

The give inequalities are:

The slopes of the first boundary line is 3 and the second is -1

Therefore the first statement is false.

Both boundary lines are solid because they contain the equality type of inequality.

The second statement is true.

(1,3) is a solution of both inequalities, because it is in the solution region

since it satisfies both inequalities.

The 3rd statement is true.

The second inequality is shaded above the boundary line because the origin does not satisfy this inequality..The two slopes are not the same so the boundary lines will intersect.

this was already solved by me with a different person. if you look it up in the search bar at the top of the page, you will get the answer.

step-by-step explanation:

answer: the answer is one of

step-by-step explanation:   we are given to write a proper fraction where the whole is divided into an even number of equal parts less than ten, and an odd number of those parts exist.

an even number less than 10 may be one of 2, 4, 6 or 8. so, the whole may be one of these four evens.

now, an odd number of these parts must exist, so the numerator must be an odd number, one of 1, 3, 5 or 7. it cannot be 9 because then the fraction will become improper.

thus, our fraction may be one of the following