Part of the area under this ramp serves for storage. Items can be stored only in the unshaded part of the ramp
shown in the diagram below. What volume of space is available for storage? Round your final answer to the
ncarest tenth of a cubic metre of usable space. Explain your answer.
3 m
No
Storage
4,5 m
Storage
3 m
5.8 m
1.7 m

( this is due tomorrow please help in the most detailed way thank you) ( 83 points)

48.1 m³ available, 2.5m³ not available

Step-by-step explanation:

Tan(X) = 4.5/(5.8+1.7)

Tan X = 3/5

Hypotenuse² = 3² + 5² = 34

Sin X = 3/sqrt(34)

X = 30.96

1/sinX = 1.7/SinY

Y = 61.003°

Third angle: 180 - X - Y = 88.037

Volume

= ½ × 1.7 × 1 × sin(88.038) × 3

= .

= 2.548

= 2.5m³

Available for storage:

½×4.5×7.5×3 - 2.548

= 48.077 = 48.1 m³

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)