Find the equation of the axis of symmetry of the following parabola algebraically.
y=2x^2-4x-14
y=2x
2
−4x−14

x = 1

Step-by-step explanation:

y = 2x² − 4x − 14

y = 2 (x² − 2x) − 14

y = 2 (x² − 2x + 1) − 14 − 2(1)

y = 2 (x − 1)² − 16

The vertex of the parabola is at (1, -16).  So the equation of the line of symmetry is x = 1.

answer: -1

step-by-step explanation:

step-by-step explanation:

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