The intensity I of light from a light bulb varies inversely as the square of the distance d from the light bulb. Suppose I is 250 250 w/m squared 2 when the distance is 3 3 m. How much farther would it be to a point where the intensity is 40 40 w/m squared 2? It would be nothing meters farther.

4.5 m

Step-by-step explanation:

I = k/d²

k = I × d²

250 × 3² = 40 × d²

d = 7.5 m

7.5 - 3 = 4.5m

answer: 12,000

step-by-step explanation: first you ar e supposed to add. then multiply then subtract

sample answer: you can determine whether each element of the domain is paired with exactly one element of the range. for example, if given a graph, you could use the vertical line test; if a vertical line intersects the graph more than once, then the relation that the graph represents is not a function.