The lees have three children. The oldest is three times older than the youngest. The middle child is eight years older than the youngest. If the sum of the ages is 43, how old is each child?

21, 15, 7

Step-by-step explanation:

you can write it as a a system of equations

x=older child y= younger child m=middle child

x=3y (oldest age is 3 times the youngest)

m=y+8 (middle is 8 years older than the youngest)

x+y+m=43 (sum of their ages = 43)

rewrite the third in terms of the youngest

3y + y + (y+8) = 43

5y = 35 therefore y=35/7=7

then

m=y+8= 7+8= 15

x=3y=3*7=21

  y= -3x is the required function.

step-by-step explanation:

we have been given a table:

x             y

0             0

1             -3

3             -9

-2             6

we can see that the values of y is -3 times the value of x

hence, the function would be: y= -3x.

put the values of x will give the same y as in the table that means function is satisfying the given table.