In construction, floor space must be given for staircases. If the second floor is 3.6 meters above the first
floor and a contractor is using the standard step pattern of 28 cm of tread for 18 cm of rise then how many
steps are needed to get from the tirst to the second floor and how much linear distance will need to be used
for the staircase?
How long would a mailing be that was parallel to the steps in the previous question?

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl

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step-by-step explanation:

c.

step-by-step explanation:

simple you would first have to get   a negative number where as 1 to be multiplied by 24 and then you would have to multiply 6 time 4 and then repeat that process until you reach your term