The graph of a system of equations shows the solution to be at (-6,2) which two of the following equations could make up this system? THERE ARE 2.

A. 2x-3y=-6
B. 4x-y=26
C. 3x+2y=-14
D. X-y=-2
E. X+y=-4

C and E

Step-by-step explanation:

Substitute (- 6, 2) into the left side of each equation and if equal to the right side then that is a possible equation

A

2(- 6) - 3(2) = - 12 - 6 = - 18 ≠ - 6

B

4(- 6) - 2 = - 24 - 2 = - 26 ≠ 26

C

3(- 6) + 2(2) = - 18 + 4 = - 14 ← this is correct

D

- 6 - 2 = - 8 ≠ - 2

E

- 6 + 2 = - 4 ← This is correct

Thus the 2 possible equations are C and E

C & E

Step-by-step explanation:

3(-6) + 2(2) = -14

-6 + 2 = -4

answer: no, but if it does it's a obvious pattern.

step-by-step explanation:

the formula for the equation of a circle is (x – h)2+ (y – k)2 = r2, where (h, k) represents the coordinates of the center of the circle, and r represents the radius of the circle. if a circle is tangent to the x-axis at (3,0), this means it touches the x-axis at that point.