Multiplication in GF(24 ): Compute A(x)B(x) mod P(x) in GF(24 ) using the irreducible polynomial P(x) = x 4 + x + 1, where A(x) = x2 + 1, and B(x) = x3 + x + 1

Step-by-step explanation:

hello,

i advice you check the question again if it is GF() or GF(24). i believe the question should rather be in this form;

multiplication in GF(): Compute A(x)B(x) mod P(x) = + +1, where A(x)=+1, and B(x)=.

i will solve the above question and i believe with this you will be able to solve any related problem.

A(x)B(x)=

=

=

please note that the division by the modulus above we used

goog may have it for you