Suppose that the following relations are defined on the set A = {1, 2, 3, 4}.R1={(2,2),(2,3),(2,4),(3,2),(3,3 ),(3,4)},
R2={(1,1),(1,2),(2,1),(2,2),(3,3),( 4,4)},
R3={(2,4),(4,2)} ,
R4={(1,2),(2,3),(3,4)},
R5={(1,1),(2,2),(3,3),(4,4)},
R6={(1,3),(1,4),(2,3),(2,4),(3,1),( 3,4)},

Determine which of these statements are correct.
Type ALL correct answers below.

A. R1 is not symmetric

B. R3 is symmetric

C. R3 is transitive

D. R2 is reflexive

E. R4 is symmetric

F. R1 is reflexive

G. R5 is not reflexive

H. R5 is transitive

I. R3 is reflexive

J. R2 is not transitive

K. R4 is transitive

L. R4 is antisymmetric

M. R6 is symmetric

R1 is symmetric,  R3 is symetric, R3 is symmetric, R5 is reflexive, R4 is antisymmetric,

Step-by-step explanation:

A relation R over set A is symmetric if for all x, y from A the following is true: (x,y) is in R implies (y,x) is in R. Definition 2: A relation R over set A is symmetric if for all x, y from A the following is true: if (x,y) is in R, then (y,x) is in R.

a set A is called transitive if either of the following equivalent conditions hold: whenever x ∈ A, and y ∈ x, then y ∈ A. whenever x ∈ A, and x is not an element, then x is a subset of A.

Reflexive relation on set is a binary element in which every element is related to itself. Let A be a set and R be the relation defined in it. R is set to be reflexive, if (a, a) ∈ R for all a ∈ A that is, every element of A is R-related to itself.

A relation R on a set A is called antisymmetric if and only if for any a, and b in A, whenever <a, b> R , and <b, a> R , a = b must hold. Equivalently, R is antisymmetric if and only if whenever <a, b> R , and a b , <b, a> R .

he sells x mount because thats eqivilqant to the maz and then divided into quarters

step-by-step explanation:

answer is 12345678900987654321234567890987654321

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