Hi friends,
I have to hand this homework as soon as possible and..i am really struggling!
If anyone accept to guide me through the way of solving this simultaneous equation, i would be really pleased.
i am in year 10 and preparing for my gcse next year but i can't go further without understanding these.
Thank you for helping me.
From Vithuna

I've been working on this for a few days and i just don't understand, it's due in a few hours. you. the direction of a vector is defined as the angle of the vector in relation to a horizontal line. as a standard, this angle is measured counterclockwise from the positive x-axis. the direction or angle of v in the diagram is α. part a: how can you use trigonometric ratios to calculate the direction α of a general vector v = < x, y> similar to the diagram? part b suppose that vector v lies in quadrant ii, quadrant iii, or quadrant iv. how can you use trigonometric ratios to calculate the direction (i.e., angle) of the vector in each of these quadrants with respect to the positive x-axis? the angle between the vector and the positive x-axis will be greater than 90 degrees in each case. part c now try a numerical problem. what is the direction of the vector w = < -1, 6 > ?

Several paint mixtures are made by mixing blue paint and white paint. paint colors blue paint white paint mixture a 5 cups 12 cups mixture b 6 cups 6 cups mixture c 4 cups 12 cups mixture d 5 cups 6 cups which mixture has the highest ratio of blue paint to white paint

Circle the problem that uses competition. 7. 32.7+15.6=32.6+15.7 45.7+26.2=45.7+26.3-0.1 8. 14.24-11.8=14.24-12+0.2 168.3-53.8=168.3-53.4-0.4