Passes through (-3,0) (-1,0) (-5,-16)
its graphing quadratics HELP

y=-2x^2-8x-6

Step-by-step explanation:

We already have two x intercepts (-3,0) and (-1,0):

(-3,0) is the solution to x+3=0

(-1,0) is the solution to x+1=0

So what we have so far is (x+3)(x+1)=y

Now we do (x+3)(x+1)*?=y

Plug in (-5,-16):

(-5+3)(-5+1)*x=-16

(-2)(-4)*x=-16

8*x=-16

x=-2

So the equation is y=(x+3)(x+1)*-2 which is y=-2x^2-8x-6

Another possible graph is y=(x+1)(x+3)(x+3) or y=x^3+7x^2+15x+9

point a is the center of the circle that passes through points e, f, and g and the center of the circle that passes through points x, y, and z.