A ball is launched as a projectile with initial speed v at an angle θ above the horizontal. Using conservation of energy, find the maximum height hmax of the ball's flight.

let's solve your equation step-by-step.

4x+2=2x+12

step 1: subtract 2x from both sides.

4x+2−2x=2x+12−2x

2x+2=12

step 2: subtract 2 from both sides.

2x+2−2=12−2

2x=10

step 3: divide both sides by 2.

2x

2

=

10

2

x=5

step-by-step explanation:

10000

step-by-step explanation: divide by 2,

don't report but were is the digram

step-by-step explanation: