Two vectors A S and B S have magnitudes A = 3.00 and B = 3.00. Their vector product is A S : B S = -5.00k n + 2.00nd. What is the angle between A S and B S ?

a

step-by-step explanation:

u take $30 minus $24. the answer/original($30)

the answer is y = 11.54

hope this : )

the answer is c.

step-by-step explanation:

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°