The yield in pounds from a day's production is normally distributed with a mean of 1500 pounds and standard deviation of 100 pounds. Assume that the yields on different days are independent random variables. Round the answers to 3 significant digits. (a) What is the probability that the production yield exceeds 1500 pounds on each of five days next week

It appears that the question is incomplete but the answer to the part given is as below.

(a) 0.0313

Step-by-step explanation:

In a normal distribution curve, the mean divides the curve into two equal parts. Hence, the probability of being lesser or higher than the mean is 1/2. This is the probability for a single day.

From the question, the probability of a day is independent of that of another day. For 5 days, the probability is

to 3 significant digits.

answer: hey there,

the answer you are looking for is a..

hope this you!

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3