Triangle BAC was dilated from triangle BDE at a scale factor of 2. What proportion proves that cos∠D = cos∠A?

Triangles BDE and BAC, in which angle B is a right angle, point D is between points B and A, and point E is between points B and C; BD measures 2 units, BE measures 3 units, and DE measures 3 and 61 hundredths units.

2/3.61 = 4/7.22

3/2 = 6/4

3/3.61 = 6/7.22

2/3 = 4/6

2/3.61 = 4/7.22

Step-by-step explanation:

Triangle BAC was dilated from triangle BDE, then side BA is 2*2 = 4 units long and side CA is 2*3.61 = 7.22 units long

Cosine of angle Ф is calculated as follows:

cos Ф = adjacent/hypotenuse

For angle D:

cos D = BD/ED = 2/3.61

For angle A:

cos A = BA/CA = 4/7.22 = 2/3.61 = cos D

sorry not sure

step-by-step explanation:

idk

step-by-step explanation: